To achieve a power factor of 0.95 from 0.75, how much KVAR is required for a 750 KVA load?

To determine the amount of reactive power (KVAR) necessary to improve the power factor from 0.75 to 0.95 for a 750 KVA load, it is essential to use the concept of apparent power (S), real power (P), and reactive power (Q).

First, compute the real power (P) using the initial power factor of 0.75. The formula for real power is:

[ P = S \times \text{Power Factor} ]

[ P = 750 , \text{KVA} \times 0.75 = 562.5 , \text{KW} ]

Next, calculate the initial reactive power (Q) using the formula that relates S, P, and Q:

[ S^2 = P^2 + Q^2 ]

Rearranging gives:

[ Q = \sqrt{S^2 - P^2} ]

[ Q = \sqrt{750^2 - 562.5^2} ]

[ Q = \sqrt{562500 - 316406.25} ]

[ Q \approx \sqrt{246093.75} \approx 496.08 , \text{